What are the solutions to the equation 5x^2+9x=-2 ?

The solutions to the equation 5x^2+9x=-2 are x=(-9+sqrt(41))/(10),x=(-9-sqrt(41))/(10)

Find the zeros of 5x^2+9x=-2

The zeros of 5x^2+9x=-2 are x=(-9+sqrt(41))/(10),x=(-9-sqrt(41))/(10)

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5 x^{2} + 9 x = - 2

x = \frac{- 9 + 41}{10}, x = \frac{- 9 - 41}{10}

Decimal Notation

x = - 0.25968 \dots, x = - 1.54031 \dots

Solution steps

5 x^{2} + 9 x = - 2

Move

2

to the left side

5 x^{2} + 9 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

9^{2} - 4 \cdot 5 \cdot 2 = 41

x_{1, 2} = \frac{- 9 \pm 41}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 41}{2 \cdot 5}, x_{2} = \frac{- 9 - 41}{2 \cdot 5}

x = \frac{- 9 + 41}{2 \cdot 5} : \frac{- 9 + 41}{10}

x = \frac{- 9 - 41}{2 \cdot 5} : \frac{- 9 - 41}{10}

The solutions to the quadratic equation are:

x = \frac{- 9 + 41}{10}, x = \frac{- 9 - 41}{10}

352

4 - \frac{x + 2}{4} = x - 4

\frac{1}{8 ^{- 9}}

1500 = x^{2} + 20 x

∣ - x - 3 ∣ = 5

What are the solutions to the equation 5x^2+9x=-2 ?
The solutions to the equation 5x^2+9x=-2 are x=(-9+sqrt(41))/(10),x=(-9-sqrt(41))/(10)
Find the zeros of 5x^2+9x=-2
The zeros of 5x^2+9x=-2 are x=(-9+sqrt(41))/(10),x=(-9-sqrt(41))/(10)