What is (1+i)/i-4/(5-i) ?

The solution to (1+i)/i-4/(5-i) is 3/13-15/13 i

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simplify (1+i)/i-4/(5-i)

simplify

\frac{1 + i}{i} - \frac{4}{5 - i}

\frac{3}{13} - \frac{15}{13} i

Solution steps

\frac{1 + i}{i} - \frac{4}{5 - i}

\frac{1 + i}{i} = - i + 1

\frac{4}{5 - i} = \frac{2 ( 5 + i )}{13}

= - i + 1 - \frac{2 ( 5 + i )}{13}

Join

- i + 1 - \frac{2 ( 5 + i )}{13} : \frac{- 15 i + 3}{13}

= \frac{- 15 i + 3}{13}

Rewrite in standard complex form:

\frac{3}{13} - \frac{15}{13} i

= \frac{3}{13} - \frac{15}{13} i

\frac{5 ( x - 4 )}{2} \geq \frac{2 x}{7} - 15

- 4 x^{2} + 12 x - 9 = 0 x

2 \frac{π}{\frac{1}{2}}

\frac{5 !}{( 5 - 3 ) ! 3 !}

5 + x = 26