What is ((x^3y^4z^6)/(xy^{-2)z^3})^2 ?

The solution to ((x^3y^4z^6)/(xy^{-2)z^3})^2 is x^4y^{12}z^6

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simplify ((x^3y^4z^6)/(xy^{-2)z^3})^2

simplify

(\frac{x ^{3} y ^{4} z ^{6}}{x y ^{- 2} z ^{3}})^{2}

x^{4} y^{12} z^{6}

Solution steps

(\frac{x ^{3} y ^{4} z ^{6}}{x y ^{- 2} z ^{3}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( x ^{3} y ^{4} z ^{6} ) ^{2}}{( x y ^{- 2} z ^{3} ) ^{2}}

Simplify

(x^{3} y^{4} z^{6})^{2} : x^{6} y^{8} z^{12}

= \frac{x ^{6} y ^{8} z ^{12}}{( x y ^{- 2} z ^{3} ) ^{2}}

Simplify

(x y^{- 2} z^{3})^{2} : \frac{x ^{2} z ^{6}}{y ^{4}}

= \frac{x ^{6} y ^{8} z ^{12}}{\frac{x ^{2} z ^{6}}{y ^{4}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{x ^{6} y ^{8} z ^{12} y ^{4}}{x ^{2} z ^{6}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{x ^{6}}{x ^{2}} = x^{6 - 2}

= \frac{y ^{8} y ^{4} z ^{12} x ^{6 - 2}}{z ^{6}}

Subtract the numbers:

6 - 2 = 4

= \frac{x ^{4} y ^{8} y ^{4} z ^{12}}{z ^{6}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{z ^{12}}{z ^{6}} = z^{12 - 6}

= x^{4} y^{8} y^{4} z^{12 - 6}

Subtract the numbers:

12 - 6 = 6

= x^{4} y^{8} y^{4} z^{6}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{8} y^{4} = y^{8 + 4}

= x^{4} y^{8 + 4} z^{6}

Add the numbers:

8 + 4 = 12

= x^{4} y^{12} z^{6}

ln (0.00001)

42 x^{3} - 7 x^{2} + 28 x

∣ 6 m ∣ = 42

(2 x)^{2}

(2^{3} + 1^{3})^{\frac{1}{3}} = 2 + 1

What is ((x^3y^4z^6)/(xy^{-2)z^3})^2 ?
The solution to ((x^3y^4z^6)/(xy^{-2)z^3})^2 is x^4y^{12}z^6