What are the solutions to the equation 4x^2+8x-7=0 ?

The solutions to the equation 4x^2+8x-7=0 are x=(-2+sqrt(11))/2 ,x=-(2+sqrt(11))/2

Find the zeros of 4x^2+8x-7=0

The zeros of 4x^2+8x-7=0 are x=(-2+sqrt(11))/2 ,x=-(2+sqrt(11))/2

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4 x^{2} + 8 x - 7 = 0

x = \frac{- 2 + 11}{2}, x = - \frac{2 + 11}{2}

Decimal Notation

x = 0.65831 \dots, x = - 2.65831 \dots

Solution steps

4 x^{2} + 8 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 7) = 411

x_{1, 2} = \frac{- 8 \pm 4 11}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4 11}{2 \cdot 4}, x_{2} = \frac{- 8 - 4 11}{2 \cdot 4}

x = \frac{- 8 + 4 11}{2 \cdot 4} : \frac{- 2 + 11}{2}

x = \frac{- 8 - 4 11}{2 \cdot 4} : - \frac{2 + 11}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 11}{2}, x = - \frac{2 + 11}{2}

2 a^{2} - 6 a - 24 = - 4

2 x^{2} + 4 x - 11 = 0

4 x^{2} + 36 x + 72

\frac{( 3 \cdot 1 0 ^{4} ) ( 5 \cdot 1 0 ^{- 2} )}{2 \cdot 1 0 ^{5}}

∣ 5 y - 8 ∣ = ∣ 8 - 5 y ∣

What are the solutions to the equation 4x^2+8x-7=0 ?
The solutions to the equation 4x^2+8x-7=0 are x=(-2+sqrt(11))/2 ,x=-(2+sqrt(11))/2
Find the zeros of 4x^2+8x-7=0
The zeros of 4x^2+8x-7=0 are x=(-2+sqrt(11))/2 ,x=-(2+sqrt(11))/2