What are the solutions to the equation 144x^2-81=0 ?

The solutions to the equation 144x^2-81=0 are x= 3/4 ,x=-3/4

Find the zeros of 144x^2-81=0

The zeros of 144x^2-81=0 are x= 3/4 ,x=-3/4

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144 x^{2} - 81 = 0

x = \frac{3}{4}, x = - \frac{3}{4}

Decimal Notation

x = 0.75, x = - 0.75

Solution steps

144 x^{2} - 81 = 0

Move

81

to the right side

144 x^{2} = 81

Divide both sides by

144

x^{2} = \frac{9}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{16}, x = - \frac{9}{16}

\frac{9}{16} = \frac{3}{4}

- \frac{9}{16} = - \frac{3}{4}

x = \frac{3}{4}, x = - \frac{3}{4}

\frac{1}{7} - 2

\frac{25 x ^{2} - 49}{x ^{2} - 36} \leq 0

24 \cdot 8

\frac{x - 1}{x ^{2} - 4} < 0

\frac{5}{2 - 1}

What are the solutions to the equation 144x^2-81=0 ?
The solutions to the equation 144x^2-81=0 are x= 3/4 ,x=-3/4
Find the zeros of 144x^2-81=0
The zeros of 144x^2-81=0 are x= 3/4 ,x=-3/4