What are the solutions to the equation 12^2+10^2=c^2 ?

The solutions to the equation 12^2+10^2=c^2 are c=2sqrt(61),c=-2sqrt(61)

Find the zeros of 12^2+10^2=c^2

The zeros of 12^2+10^2=c^2 are c=2sqrt(61),c=-2sqrt(61)

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1 2^{2} + 1 0^{2} = c^{2}

c = 261, c = - 261

Decimal Notation

c = 15.62049 \dots, c = - 15.62049 \dots

Solution steps

1 2^{2} + 1 0^{2} = c^{2}

Switch sides

c^{2} = 1 2^{2} + 1 0^{2}

Simplify

1 2^{2} + 1 0^{2} : 244

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 244, c = - 244

244 = 261

- 244 = - 261

c = 261, c = - 261

x + h

X^{2} + X - 3 = 0

lo g_{36} (6)

(- a^{2} - 5 ab + 3 b^{2}) - (3 a^{2} - 2 ab + 3 b^{2})

\frac{1}{2} \cdot \frac{3}{4}

What are the solutions to the equation 12^2+10^2=c^2 ?
The solutions to the equation 12^2+10^2=c^2 are c=2sqrt(61),c=-2sqrt(61)
Find the zeros of 12^2+10^2=c^2
The zeros of 12^2+10^2=c^2 are c=2sqrt(61),c=-2sqrt(61)