What are the solutions to the equation -4.9t^2+20=0 ?

The solutions to the equation -4.9t^2+20=0 are t=(10sqrt(2))/7 ,t=-(10sqrt(2))/7

Find the zeros of -4.9t^2+20=0

The zeros of -4.9t^2+20=0 are t=(10sqrt(2))/7 ,t=-(10sqrt(2))/7

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- 4.9 t^{2} + 20 = 0

t = \frac{10 2}{7}, t = - \frac{10 2}{7}

Decimal Notation

t = 2.02030 \dots, t = - 2.02030 \dots

Solution steps

- 4.9 t^{2} + 20 = 0

Move

20

to the right side

- 4.9 t^{2} = - 20

Multiply both sides by

10

- 49 t^{2} = - 200

Divide both sides by

- 49

t^{2} = \frac{200}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{200}{49}, t = - \frac{200}{49}

\frac{200}{49} = \frac{10 2}{7}

- \frac{200}{49} = - \frac{10 2}{7}

t = \frac{10 2}{7}, t = - \frac{10 2}{7}

(3)^{2} + (3)

\frac{1}{2} ∣ 3 c + 5 ∣ = 6 c + 4

3 - x^{2} = 6 - 4 x

2 w^{2} - 3 w - 527 = 0

x^{3} - 5 x^{2} + 5 x - 25

What are the solutions to the equation -4.9t^2+20=0 ?
The solutions to the equation -4.9t^2+20=0 are t=(10sqrt(2))/7 ,t=-(10sqrt(2))/7
Find the zeros of -4.9t^2+20=0
The zeros of -4.9t^2+20=0 are t=(10sqrt(2))/7 ,t=-(10sqrt(2))/7