What are the solutions to the equation 3-x^2=6-4x ?

The solutions to the equation 3-x^2=6-4x are x=1,x=3

Find the zeros of 3-x^2=6-4x

The zeros of 3-x^2=6-4x are x=1,x=3

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3 - x^{2} = 6 - 4 x

x = 1, x = 3

Solution steps

3 - x^{2} = 6 - 4 x

Move

4 x

to the left side

3 - x^{2} + 4 x = 6

Move

6

to the left side

- x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

4^{2} - 4 (- 1) (- 3) = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2}{2 ( - 1 )}

x = \frac{- 4 + 2}{2 ( - 1 )} : 1

x = \frac{- 4 - 2}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = 1, x = 3

2 w^{2} - 3 w - 527 = 0

x^{3} - 5 x^{2} + 5 x - 25

\frac{x + 1}{3} - \frac{x - 1}{4} < x + \frac{x + 1}{2}

\frac{9}{6}

\frac{d}{d x} (x (A + B))

What are the solutions to the equation 3-x^2=6-4x ?
The solutions to the equation 3-x^2=6-4x are x=1,x=3
Find the zeros of 3-x^2=6-4x
The zeros of 3-x^2=6-4x are x=1,x=3