What is (x+1)/3-(x-1)/4 <x+(x+1)/2 ?

The solution to (x+1)/3-(x-1)/4 1/17

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(x+1)/3-(x-1)/4 <x+(x+1)/2

\frac{x + 1}{3} - \frac{x - 1}{4} < x + \frac{x + 1}{2}

x > \frac{1}{17}

Interval Notation

(\frac{1}{17}, \infty)

Decimal Notation

x > 0.05882 \dots

Solution steps

\frac{x + 1}{3} - \frac{x - 1}{4} < x + \frac{x + 1}{2}

Multiply by LCM

4 (x + 1) - 3 (x - 1) < 12 x + 6 (x + 1)

Expand

6 (x + 1) : 6 x + 6

x + 7 < 12 x + 6 x + 6

Add similar elements:

12 x + 6 x = 18 x

x + 7 < 18 x + 6

Expand

4 (x + 1) - 3 (x - 1) : x + 7

x + 7 < 18 x + 6

Move

7

to the right side

x < 18 x - 1

Move

18 x

to the left side

- 17 x < - 1

Multiply both sides by

- 1

17 x > 1

Divide both sides by

17

x > \frac{1}{17}

\frac{9}{6}

\frac{d}{d x} (x (A + B))

x^{2} + 22 x + 121 = 15

4 a - \frac{a ^{2}}{2} = 1

t^{2} + 9 t + 18

What is (x+1)/3-(x-1)/4 <x+(x+1)/2 ?
The solution to (x+1)/3-(x-1)/4 <x+(x+1)/2 is x> 1/17