What are the solutions to the equation x^2-15x+50=0 ?

The solutions to the equation x^2-15x+50=0 are x=10,x=5

Find the zeros of x^2-15x+50=0

The zeros of x^2-15x+50=0 are x=10,x=5

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x^{2} - 15 x + 50 = 0

x = 10, x = 5

Solution steps

x^{2} - 15 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 50 = 5

x_{1, 2} = \frac{- ( - 15 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 5}{2 \cdot 1}

x = \frac{- ( - 15 ) + 5}{2 \cdot 1} : 10

x = \frac{- ( - 15 ) - 5}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 10, x = 5

4 + 2 d = 8

16 y x^{4} + 12 y^{3} x^{2} - 20 y x

∣ w ∣ = 0

(x + 3)^{3}

\frac{- 1}{2} < \frac{2 x + 3}{5} < \frac{3}{2}

What are the solutions to the equation x^2-15x+50=0 ?
The solutions to the equation x^2-15x+50=0 are x=10,x=5
Find the zeros of x^2-15x+50=0
The zeros of x^2-15x+50=0 are x=10,x=5