en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-8x+17>0

Solution

x^{2} - 8 x + 17 > 0

Solution

True for all x

+1

Interval Notation

(- \infty, \infty)

Solution steps

x^{2} - 8 x + 17 > 0

Complete the square

x^{2} - 8 x + 17 : (x - 4)^{2} + 1

(x - 4)^{2} + 1 > 0

Move

1

to the right side

(x - 4)^{2} > - 1

If n is even,

u^{n} \geq 0

for all

u

True for all x

Popular Examples

5 u + 16 = 3 u + 6 u - 12

simplify ((3i)/n)^2 simplify

(\frac{3 i}{n})^{2}

simplify (m^{1/3})^{1/5}simplify

(m^{\frac{1}{3}})^{\frac{1}{5}}

- 2 x - 1 = 0

x(x^2+x)-(x+1)(x^2-2)=-4

x (x^{2} + x) - (x + 1) (x^{2} - 2) = - 4

Frequently Asked Questions (FAQ)

What is x^2-8x+17>0 ?
The solution to x^2-8x+17>0 is True for all x