What is 3x+7<=-2\land 2x<= 0 ?

The solution to 3x+7<=-2\land 2x<= 0 is x<=-3

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3x+7<=-2\land 2x<= 0

3 x + 7 \leq - 2 and 2 x \leq 0

x \leq - 3

Interval Notation

(- \infty, - 3]

Solution steps

3 x + 7 \leq - 2 and 2 x \leq 0

3 x + 7 \leq - 2 : x \leq - 3

2 x \leq 0 : x \leq 0

Combine the intervals

x \leq - 3 and x \leq 0

Merge Overlapping Intervals

x \leq - 3

\frac{3 x + 1}{7} - \frac{2 - 4 x}{3} = \frac{5 x - 4}{14} + \frac{7 x}{6}

(4 + i) - (3 - 5 i) (- 2 + 5 i)

5 x < 10

x (x - 2)^{2} > 0

lo g_{7} (0)