What are the solutions to the equation t^2-7t=0 ?

The solutions to the equation t^2-7t=0 are t=7,t=0

Find the zeros of t^2-7t=0

The zeros of t^2-7t=0 are t=7,t=0

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t^{2} - 7 t = 0

t = 7, t = 0

Solution steps

t^{2} - 7 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 0 = 7

t_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 1}, t_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 1}

t = \frac{- ( - 7 ) + 7}{2 \cdot 1} : 7

t = \frac{- ( - 7 ) - 7}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 7, t = 0

\frac{1}{6} p = \frac{1}{5} p + \frac{2}{3}

4 (p - 6 p^{2} q) - 9 - 9 pq + 7 p (p + q) - 5 (3 + pq)

x^{2} - 18 x - 4 = 0

(1 + i) (1 - i)

∣ x ∣ > 11

What are the solutions to the equation t^2-7t=0 ?
The solutions to the equation t^2-7t=0 are t=7,t=0
Find the zeros of t^2-7t=0
The zeros of t^2-7t=0 are t=7,t=0