What are the solutions to the equation m^2-4m=0 ?

The solutions to the equation m^2-4m=0 are m=4,m=0

Find the zeros of m^2-4m=0

The zeros of m^2-4m=0 are m=4,m=0

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m^{2} - 4 m = 0

m = 4, m = 0

Solution steps

m^{2} - 4 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

m_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, m_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

m = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

m = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

m = 4, m = 0

- 9 x^{2} + 12 x - 4 = 0

x^{5} y^{2} + x^{2} y^{5}

a^{2} - 4

lo g_{11} (11)

9 2^{2} + x^{2} = 15 2^{2}

What are the solutions to the equation m^2-4m=0 ?
The solutions to the equation m^2-4m=0 are m=4,m=0
Find the zeros of m^2-4m=0
The zeros of m^2-4m=0 are m=4,m=0