What is (y^{-2}z^{-3})/(y^{-1)} ?

The solution to (y^{-2}z^{-3})/(y^{-1)} is 1/(z^3y)

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simplify (y^{-2}z^{-3})/(y^{-1)}

simplify

\frac{y ^{- 2} z ^{- 3}}{y ^{- 1}}

\frac{1}{z ^{3} y}

Solution steps

\frac{y ^{- 2} z ^{- 3}}{y ^{- 1}}

Simplify

\frac{y ^{- 2}}{y ^{- 1}} : \frac{1}{y}

= \frac{z ^{- 3}}{y}

Simplify

\frac{z ^{- 3}}{y} : \frac{1}{z ^{3} y}

= \frac{1}{z ^{3} y}

\frac{2 x - 5}{12} > \frac{- x}{4} - \frac{5}{3}

23 + 1 = 9

f^{- 1} (3)

(3 x - 1) = 0

\frac{6 ^{2}}{6 ^{2} - 4} - \frac{1}{6 - 2}

What is (y^{-2}z^{-3})/(y^{-1)} ?
The solution to (y^{-2}z^{-3})/(y^{-1)} is 1/(z^3y)