What are the solutions to the equation x^2+67=18x ?

The solutions to the equation x^2+67=18x are x=9+sqrt(14),x=9-sqrt(14)

Find the zeros of x^2+67=18x

The zeros of x^2+67=18x are x=9+sqrt(14),x=9-sqrt(14)

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x^{2} + 67 = 18 x

x = 9 + 14, x = 9 - 14

Decimal Notation

x = 12.74165 \dots, x = 5.25834 \dots

Solution steps

x^{2} + 67 = 18 x

Move

18 x

to the left side

x^{2} + 67 - 18 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 18 x + 67 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 67}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 67 = 214

x_{1, 2} = \frac{- ( - 18 ) \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 14}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 14}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 14}{2 \cdot 1} : 9 + 14

x = \frac{- ( - 18 ) - 2 14}{2 \cdot 1} : 9 - 14

The solutions to the quadratic equation are:

x = 9 + 14, x = 9 - 14

- 4 < 2 x - 1 < 3

3 t^{2} - 24 t + 45 = 0

- \frac{18}{15}

2 x^{3} + 9 x^{2} - 35 x \geq 0

2 x^{2} - 2 x + 13 = 0

What are the solutions to the equation x^2+67=18x ?
The solutions to the equation x^2+67=18x are x=9+sqrt(14),x=9-sqrt(14)
Find the zeros of x^2+67=18x
The zeros of x^2+67=18x are x=9+sqrt(14),x=9-sqrt(14)