What are the solutions to the equation 0=x^2-6x+6 ?

The solutions to the equation 0=x^2-6x+6 are x=3+sqrt(3),x=3-sqrt(3)

Find the zeros of 0=x^2-6x+6

The zeros of 0=x^2-6x+6 are x=3+sqrt(3),x=3-sqrt(3)

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0 = x^{2} - 6 x + 6

x = 3 + 3, x = 3 - 3

Decimal Notation

x = 4.73205 \dots, x = 1.26794 \dots

Solution steps

0 = x^{2} - 6 x + 6

Switch sides

x^{2} - 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 6 = 23

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 3}{2 \cdot 1} : 3 + 3

x = \frac{- ( - 6 ) - 2 3}{2 \cdot 1} : 3 - 3

The solutions to the quadratic equation are:

x = 3 + 3, x = 3 - 3

2 x^{2} - 3 x = (x - 1) (x - 1) + (6 x^{2} - 5)

∣ x + 1 ∣ > 4

\frac{( x - 6 ) ( x + 2 )}{x - 4} \leq 0

3 x + 1 - 5 x = - 11 + x

\frac{7}{9} x - \frac{1}{2} (x + 5) \leq \frac{5}{18}

What are the solutions to the equation 0=x^2-6x+6 ?
The solutions to the equation 0=x^2-6x+6 are x=3+sqrt(3),x=3-sqrt(3)
Find the zeros of 0=x^2-6x+6
The zeros of 0=x^2-6x+6 are x=3+sqrt(3),x=3-sqrt(3)