What is factor a^9+b^9 ?

The solution to factor a^9+b^9 is (a+b)(a^2-ab+b^2)(a^6-a^3b^3+b^6)

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factor a^9+b^9

factor

a^{9} + b^{9}

(a + b) (a^{2} - ab + b^{2}) (a^{6} - a^{3} b^{3} + b^{6})

Solution steps

a^{9} + b^{9}

Apply exponent rules

= (a^{3})^{3} + (b^{3})^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(a^{3})^{3} + (b^{3})^{3} = (a^{3} + b^{3}) ((a^{3})^{2} - a^{3} b^{3} + (b^{3})^{2})

= (a^{3} + b^{3}) ((a^{3})^{2} - a^{3} b^{3} + (b^{3})^{2})

Simplify

(a^{3})^{2} - a^{3} b^{3} + (b^{3})^{2} : a^{6} - a^{3} b^{3} + b^{6}

= (a^{3} + b^{3}) (a^{6} - a^{3} b^{3} + b^{6})

Factor

a^{3} + b^{3} : (a + b) (a^{2} - ab + b^{2})

= (a + b) (a^{2} - ab + b^{2}) (a^{6} - a^{3} b^{3} + b^{6})

2 x + 1 = 2 x - 1

10 x^{2} - 9 x - 9

3^{2} + 2^{2} = x^{2}

6 (u + 1) - 10 = 4 (u - 1) + 2 u

3 x^{2} - 19 x - 14

What is factor a^9+b^9 ?
The solution to factor a^9+b^9 is (a+b)(a^2-ab+b^2)(a^6-a^3b^3+b^6)