What are the solutions to the equation 98=7v^2+42 ?

The solutions to the equation 98=7v^2+42 are v=2sqrt(2),v=-2sqrt(2)

Find the zeros of 98=7v^2+42

The zeros of 98=7v^2+42 are v=2sqrt(2),v=-2sqrt(2)

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98 = 7 v^{2} + 42

v = 22, v = - 22

Decimal Notation

v = 2.82842 \dots, v = - 2.82842 \dots

Solution steps

98 = 7 v^{2} + 42

Switch sides

7 v^{2} + 42 = 98

Move

42

to the right side

7 v^{2} = 56

Divide both sides by

7

v^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = 8, v = - 8

8 = 22

- 8 = - 22

v = 22, v = - 22

(x + 5)^{2} = 4 x^{2}

∣ 5 + 2 x ∣ \geq 3

∣ 7 x - 5 ∣ + 5 = 8

\frac{1}{9} (2 m - 16) = \frac{1}{3} (2 m + 4)

(- 6)^{2}

What are the solutions to the equation 98=7v^2+42 ?
The solutions to the equation 98=7v^2+42 are v=2sqrt(2),v=-2sqrt(2)
Find the zeros of 98=7v^2+42
The zeros of 98=7v^2+42 are v=2sqrt(2),v=-2sqrt(2)