What is 1/4 (x-1)^2<= 1 ?

The solution to 1/4 (x-1)^2<= 1 is -1<= x<= 3

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1/4 (x-1)^2<= 1

\frac{1}{4} (x - 1)^{2} \leq 1

- 1 \leq x \leq 3

Interval Notation

[- 1, 3]

Solution steps

\frac{1}{4} (x - 1)^{2} \leq 1

Multiply both sides by

4

(x - 1)^{2} \leq 4

For

u^{n} \leq a

, if

n

is even then

- 4 \leq x - 1 \leq 4

a \leq u \leq b

then

a \leq u and u \leq b

- 4 \leq x - 1 and x - 1 \leq 4

- 4 \leq x - 1 : x \geq - 1

x - 1 \leq 4 : x \leq 3

Combine the intervals

x \geq - 1 and x \leq 3

Merge Overlapping Intervals

- 1 \leq x \leq 3

- \frac{8}{1 ^{2}}

2 x^{2} + 5 x - 6 = 0

\frac{( 500 \cdot 1 2 ^{2} )}{12}

15 x - 7 = 23 x - 79

x^{3} + 8