What are the solutions to the equation 30r^2-19r-5=0 ?

The solutions to the equation 30r^2-19r-5=0 are r= 5/6 ,r=-1/5

Find the zeros of 30r^2-19r-5=0

The zeros of 30r^2-19r-5=0 are r= 5/6 ,r=-1/5

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30 r^{2} - 19 r - 5 = 0

r = \frac{5}{6}, r = - \frac{1}{5}

Solution steps

30 r^{2} - 19 r - 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 30 ( - 5 )}{2 \cdot 30}

(- 19)^{2} - 4 \cdot 30 (- 5) = 31

r_{1, 2} = \frac{- ( - 19 ) \pm 31}{2 \cdot 30}

Separate the solutions

r_{1} = \frac{- ( - 19 ) + 31}{2 \cdot 30}, r_{2} = \frac{- ( - 19 ) - 31}{2 \cdot 30}

r = \frac{- ( - 19 ) + 31}{2 \cdot 30} : \frac{5}{6}

r = \frac{- ( - 19 ) - 31}{2 \cdot 30} : - \frac{1}{5}

The solutions to the quadratic equation are:

r = \frac{5}{6}, r = - \frac{1}{5}

18 x^{2} - 6 x + 1 = 0

5 + \frac{3}{2}

2 x^{2} - 7 x - 5 = 0

\frac{3 ( x + 1 )}{6} = 2 x - 1

5 (x + 8) = 40

What are the solutions to the equation 30r^2-19r-5=0 ?
The solutions to the equation 30r^2-19r-5=0 are r= 5/6 ,r=-1/5
Find the zeros of 30r^2-19r-5=0
The zeros of 30r^2-19r-5=0 are r= 5/6 ,r=-1/5