What are the solutions to the equation x(x-1)=2 ?

The solutions to the equation x(x-1)=2 are x=2,x=-1

Find the zeros of x(x-1)=2

The zeros of x(x-1)=2 are x=2,x=-1

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x (x - 1) = 2

x = 2, x = - 1

Solution steps

x (x - 1) = 2

Expand

x (x - 1) : x^{2} - x

x^{2} - x = 2

Move

2

to the left side

x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

x = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

1 2^{2} + 5^{2} = x^{2}

0.25 x = 0.2 x + 15

32 a^{2} - 50 b^{2}

(- \frac{3}{4} p)^{3}

5 x^{3} - 5 x^{2} + 5 x - 5

What are the solutions to the equation x(x-1)=2 ?
The solutions to the equation x(x-1)=2 are x=2,x=-1
Find the zeros of x(x-1)=2
The zeros of x(x-1)=2 are x=2,x=-1