What are the solutions to the equation (x+3)(x-1)=32 ?

The solutions to the equation (x+3)(x-1)=32 are x=5,x=-7

Find the zeros of (x+3)(x-1)=32

The zeros of (x+3)(x-1)=32 are x=5,x=-7

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(x + 3) (x - 1) = 32

x = 5, x = - 7

Solution steps

(x + 3) (x - 1) = 32

Expand

(x + 3) (x - 1) : x^{2} + 2 x - 3

x^{2} + 2 x - 3 = 32

Move

32

to the left side

x^{2} + 2 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 35) = 12

x_{1, 2} = \frac{- 2 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 12}{2 \cdot 1}, x_{2} = \frac{- 2 - 12}{2 \cdot 1}

x = \frac{- 2 + 12}{2 \cdot 1} : 5

x = \frac{- 2 - 12}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 5, x = - 7

\frac{5 a ^{4}}{- 2 ( a ^{4} m ^{- 4} ) ^{- 1}}

7 x \leq 7 (x - 6)

- \frac{7}{6} - (- \frac{1}{4})

x^{\frac{1}{2}} \cdot \frac{1}{2} x^{- \frac{1}{2}}

8 x + 9 = 6 x + 27

What are the solutions to the equation (x+3)(x-1)=32 ?
The solutions to the equation (x+3)(x-1)=32 are x=5,x=-7
Find the zeros of (x+3)(x-1)=32
The zeros of (x+3)(x-1)=32 are x=5,x=-7