What are the solutions to the equation x^2+12x+24=0 ?

The solutions to the equation x^2+12x+24=0 are x=2(sqrt(3)-3),x=-2(3+sqrt(3))

Find the zeros of x^2+12x+24=0

The zeros of x^2+12x+24=0 are x=2(sqrt(3)-3),x=-2(3+sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 12 x + 24 = 0

x = 2 (3 - 3), x = - 2 (3 + 3)

Decimal Notation

x = - 2.53589 \dots, x = - 9.46410 \dots

Solution steps

x^{2} + 12 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 24 = 43

x_{1, 2} = \frac{- 12 \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 4 3}{2 \cdot 1}, x_{2} = \frac{- 12 - 4 3}{2 \cdot 1}

x = \frac{- 12 + 4 3}{2 \cdot 1} : 2 (3 - 3)

x = \frac{- 12 - 4 3}{2 \cdot 1} : - 2 (3 + 3)

The solutions to the quadratic equation are:

x = 2 (3 - 3), x = - 2 (3 + 3)

- 3 < 5 - 2 x \leq 11

- 3 (y + 5) = 15

- x^{2} + 5 x - 6 = 0

k M x - k x^{2}

35 a^{2} - 30 a - 210

What are the solutions to the equation x^2+12x+24=0 ?
The solutions to the equation x^2+12x+24=0 are x=2(sqrt(3)-3),x=-2(3+sqrt(3))
Find the zeros of x^2+12x+24=0
The zeros of x^2+12x+24=0 are x=2(sqrt(3)-3),x=-2(3+sqrt(3))