What are the solutions to the equation -x^2+5x-6=0 ?

The solutions to the equation -x^2+5x-6=0 are x=2,x=3

Find the zeros of -x^2+5x-6=0

The zeros of -x^2+5x-6=0 are x=2,x=3

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- x^{2} + 5 x - 6 = 0

x = 2, x = 3

Solution steps

- x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

5^{2} - 4 (- 1) (- 6) = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 ( - 1 )}, x_{2} = \frac{- 5 - 1}{2 ( - 1 )}

x = \frac{- 5 + 1}{2 ( - 1 )} : 2

x = \frac{- 5 - 1}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = 2, x = 3

k M x - k x^{2}

35 a^{2} - 30 a - 210

9 a^{3} - 6 a^{2}

x^{2} + 4 x - 44 = 0

5 + 5

What are the solutions to the equation -x^2+5x-6=0 ?
The solutions to the equation -x^2+5x-6=0 are x=2,x=3
Find the zeros of -x^2+5x-6=0
The zeros of -x^2+5x-6=0 are x=2,x=3