What are the solutions to the equation 3x^2+24x=0 ?

The solutions to the equation 3x^2+24x=0 are x=0,x=-8

Find the zeros of 3x^2+24x=0

The zeros of 3x^2+24x=0 are x=0,x=-8

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3 x^{2} + 24 x = 0

x = 0, x = - 8

Solution steps

3 x^{2} + 24 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 0 = 24

x_{1, 2} = \frac{- 24 \pm 24}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 24 + 24}{2 \cdot 3}, x_{2} = \frac{- 24 - 24}{2 \cdot 3}

x = \frac{- 24 + 24}{2 \cdot 3} : 0

x = \frac{- 24 - 24}{2 \cdot 3} : - 8

The solutions to the quadratic equation are:

x = 0, x = - 8

- 6 m \leq - 36 and m + 24 \leq 20

- p + 50 = 3 p - 30

\frac{x - 6}{5} = \frac{x + 1}{6}

3 x^{4} - 2 x^{3} + 11 x^{2} - 8 x - 4

(x + 2 i)^{2} (x - 2 i)^{2}

What are the solutions to the equation 3x^2+24x=0 ?
The solutions to the equation 3x^2+24x=0 are x=0,x=-8
Find the zeros of 3x^2+24x=0
The zeros of 3x^2+24x=0 are x=0,x=-8