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Popular >

(x-2)^2>(x+2)(x-2)+8

Solution

(x - 2)^{2} > (x + 2) (x - 2) + 8

Solution

x < 0

+1

Interval Notation

(- \infty, 0)

Solution steps

(x - 2)^{2} > (x + 2) (x - 2) + 8

Rewrite in standard form

- x > 0

Multiply both sides by

- 1

x < 0

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81 + 20 - 45

|b|=sqrt(0^2+0^2+3^2)

∣ b ∣ = 0^{2} + 0^{2} + 3^{2}

2 x^{2} + 2 x - 7 = 0

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- 47 \cdot 42

simplify (16)^{5/2}simplify

(16)^{\frac{5}{2}}

Frequently Asked Questions (FAQ)

What is (x-2)^2>(x+2)(x-2)+8 ?
The solution to (x-2)^2>(x+2)(x-2)+8 is x<0