What is the answer to |b|=sqrt(0^2+0^2+3^2) ?

The answer to |b|=sqrt(0^2+0^2+3^2) is b=-sqrt(0^2+0^2+3^2)\lor b=sqrt(0^2+0^2+3^2)

Solve for b: |b|=sqrt(0^2+0^2+3^2)

The solution is b=-sqrt(0^2+0^2+3^2)\lor b=sqrt(0^2+0^2+3^2)

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∣ b ∣ = 0^{2} + 0^{2} + 3^{2}

b = - 0^{2} + 0^{2} + 3^{2} or b = 0^{2} + 0^{2} + 3^{2}

Decimal Notation

b = - 3, b = 3

Solution steps

∣ b ∣ = 0^{2} + 0^{2} + 3^{2}

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

b = - 0^{2} + 0^{2} + 3^{2} or b = 0^{2} + 0^{2} + 3^{2}

2 x^{2} + 2 x - 7 = 0

- 47 \cdot 42

(16)^{\frac{5}{2}}

(\frac{3}{4})^{2} - \frac{1}{4} - (- \frac{3}{8})^{2} + (\frac{1}{4})^{3}

\frac{1}{t 1 + t} - \frac{1}{t}

What is the answer to |b|=sqrt(0^2+0^2+3^2) ?
The answer to |b|=sqrt(0^2+0^2+3^2) is b=-sqrt(0^2+0^2+3^2)\lor b=sqrt(0^2+0^2+3^2)
Solve for b: |b|=sqrt(0^2+0^2+3^2)
The solution is b=-sqrt(0^2+0^2+3^2)\lor b=sqrt(0^2+0^2+3^2)