What are the solutions to the equation 4x^2+4x+1=9 ?

The solutions to the equation 4x^2+4x+1=9 are x=1,x=-2

Find the zeros of 4x^2+4x+1=9

The zeros of 4x^2+4x+1=9 are x=1,x=-2

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4 x^{2} + 4 x + 1 = 9

x = 1, x = - 2

Solution steps

4 x^{2} + 4 x + 1 = 9

Move

9

to the left side

4 x^{2} + 4 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 8 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 8) = 12

x_{1, 2} = \frac{- 4 \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 12}{2 \cdot 4}, x_{2} = \frac{- 4 - 12}{2 \cdot 4}

x = \frac{- 4 + 12}{2 \cdot 4} : 1

x = \frac{- 4 - 12}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

- 3 x^{2} - 6 x + 4 = 0

\frac{1}{2} 4

\frac{1}{2}

\frac{30 a ^{5} \times a ^{3}}{12 a}

100 m^{8} - 9

What are the solutions to the equation 4x^2+4x+1=9 ?
The solutions to the equation 4x^2+4x+1=9 are x=1,x=-2
Find the zeros of 4x^2+4x+1=9
The zeros of 4x^2+4x+1=9 are x=1,x=-2