What are the solutions to the equation 12x^2-132x+252=0 ?

The solutions to the equation 12x^2-132x+252=0 are x=(11+sqrt(37))/2 ,x=(11-sqrt(37))/2

Find the zeros of 12x^2-132x+252=0

The zeros of 12x^2-132x+252=0 are x=(11+sqrt(37))/2 ,x=(11-sqrt(37))/2

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12 x^{2} - 132 x + 252 = 0

x = \frac{11 + 37}{2}, x = \frac{11 - 37}{2}

Decimal Notation

x = 8.54138 \dots, x = 2.45861 \dots

Solution steps

12 x^{2} - 132 x + 252 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 132 ) \pm ( - 132 ) ^{2} - 4 \cdot 12 \cdot 252}{2 \cdot 12}

(- 132)^{2} - 4 \cdot 12 \cdot 252 = 1237

x_{1, 2} = \frac{- ( - 132 ) \pm 12 37}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 132 ) + 12 37}{2 \cdot 12}, x_{2} = \frac{- ( - 132 ) - 12 37}{2 \cdot 12}

x = \frac{- ( - 132 ) + 12 37}{2 \cdot 12} : \frac{11 + 37}{2}

x = \frac{- ( - 132 ) - 12 37}{2 \cdot 12} : \frac{11 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 37}{2}, x = \frac{11 - 37}{2}

- 2 x^{2} - 4 x

\frac{10 - 75}{5}

3 h + 4 < 2 h - 1 and 7 h > 5 h

\frac{4}{25}

x^{2} - 2 x - 35 = 0

What are the solutions to the equation 12x^2-132x+252=0 ?
The solutions to the equation 12x^2-132x+252=0 are x=(11+sqrt(37))/2 ,x=(11-sqrt(37))/2
Find the zeros of 12x^2-132x+252=0
The zeros of 12x^2-132x+252=0 are x=(11+sqrt(37))/2 ,x=(11-sqrt(37))/2