What is x^3-4x^2-5x>2x ?

The solution to x^3-4x^2-5x>2x is 2-sqrt(11) 2+sqrt(11)

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x^3-4x^2-5x>2x

x^{3} - 4 x^{2} - 5 x > 2 x

2 - 11 < x < 0 or x > 2 + 11

Interval Notation

(2 - 11, 0) \cup (2 + 11, \infty)

Decimal Notation

- 1.31662 \dots < x < 0 or x > 5.31662 \dots

Solution steps

x^{3} - 4 x^{2} - 5 x > 2 x

Rewrite in standard form

x^{3} - 4 x^{2} - 7 x > 0

Factor

x^{3} - 4 x^{2} - 7 x : x (x - 2 - 11) (x - 2 + 11)

x (x - 2 - 11) (x - 2 + 11) > 0

Identify the intervals

2 - 11 < x < 0 or x > 2 + 11

∣ 3 s ∣ + 6 = 6

9 (5 x - 2)^{2} - 7 (5 x - 2) (3 x + 4)

2 (x + 2)^{2} = 32

6 x = 42

\frac{1}{5} - \frac{1}{12}

What is x^3-4x^2-5x>2x ?
The solution to x^3-4x^2-5x>2x is 2-sqrt(11)<x<0\lor x>2+sqrt(11)