What are the solutions to the equation 2(x+2)^2=32 ?

The solutions to the equation 2(x+2)^2=32 are x=2,x=-6

Find the zeros of 2(x+2)^2=32

The zeros of 2(x+2)^2=32 are x=2,x=-6

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2 (x + 2)^{2} = 32

x = 2, x = - 6

Solution steps

2 (x + 2)^{2} = 32

Divide both sides by

2

(x + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 16 : x = 2

Solve

x + 2 = - 16 : x = - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

6 x = 42

\frac{1}{5} - \frac{1}{12}

2 y - 1 = - 5

64 + (\frac{25}{3})^{2} = y^{2}

- x^{2} + 7 x - 6 = 0

What are the solutions to the equation 2(x+2)^2=32 ?
The solutions to the equation 2(x+2)^2=32 are x=2,x=-6
Find the zeros of 2(x+2)^2=32
The zeros of 2(x+2)^2=32 are x=2,x=-6