What are the solutions to the equation -x^2+7x-6=0 ?

The solutions to the equation -x^2+7x-6=0 are x=1,x=6

Find the zeros of -x^2+7x-6=0

The zeros of -x^2+7x-6=0 are x=1,x=6

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- x^{2} + 7 x - 6 = 0

x = 1, x = 6

Solution steps

- x^{2} + 7 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

7^{2} - 4 (- 1) (- 6) = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 ( - 1 )}, x_{2} = \frac{- 7 - 5}{2 ( - 1 )}

x = \frac{- 7 + 5}{2 ( - 1 )} : 1

x = \frac{- 7 - 5}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 1, x = 6

4 (4 - 6 t) + (1 + 9 t) + 2 (2 + 3 t) = 1

4 (\frac{2}{3})

w^{2} + 14 w + 49

\frac{5 x - 2}{3} - \frac{x - 8}{4} > \frac{x + 14}{2} - 2

5 - \frac{5}{3}

What are the solutions to the equation -x^2+7x-6=0 ?
The solutions to the equation -x^2+7x-6=0 are x=1,x=6
Find the zeros of -x^2+7x-6=0
The zeros of -x^2+7x-6=0 are x=1,x=6