What are the solutions to the equation x^2+17x+49=3x ?

The solutions to the equation x^2+17x+49=3x are x=-7

Find the zeros of x^2+17x+49=3x

The zeros of x^2+17x+49=3x are x=-7

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x^{2} + 17 x + 49 = 3 x

x = - 7

Solution steps

x^{2} + 17 x + 49 = 3 x

Move

3 x

to the left side

x^{2} + 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- 14 \pm 0}{2 \cdot 1}

x = \frac{- 14}{2 \cdot 1}

\frac{- 14}{2 \cdot 1} = - 7

x = - 7

The solution to the quadratic equation is:

x = - 7

0 = b^{2} + 11 b + 30

\frac{( x - 2 )}{2 x + 1} < 3

x y + 2 x + 3 y + 6

(b^{2} + 3 b) + b + 3

- 2 y - 16 > 3 y + 24

What are the solutions to the equation x^2+17x+49=3x ?
The solutions to the equation x^2+17x+49=3x are x=-7
Find the zeros of x^2+17x+49=3x
The zeros of x^2+17x+49=3x are x=-7