What are the solutions to the equation m^2+2m+6=0 ?

The solutions to the equation m^2+2m+6=0 are m=-1+sqrt(5)i,m=-1-sqrt(5)i

Find the zeros of m^2+2m+6=0

The zeros of m^2+2m+6=0 are m=-1+sqrt(5)i,m=-1-sqrt(5)i

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m^{2} + 2 m + 6 = 0

m = - 1 + 5 i, m = - 1 - 5 i

Solution steps

m^{2} + 2 m + 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 6 : 25 i

m_{1, 2} = \frac{- 2 \pm 2 5 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 2 5 i}{2 \cdot 1}, m_{2} = \frac{- 2 - 2 5 i}{2 \cdot 1}

m = \frac{- 2 + 2 5 i}{2 \cdot 1} : - 1 + 5 i

m = \frac{- 2 - 2 5 i}{2 \cdot 1} : - 1 - 5 i

The solutions to the quadratic equation are:

m = - 1 + 5 i, m = - 1 - 5 i

6 x^{2} + 72 x + 210 = 0

- \frac{1}{2} < \frac{4 - 3 x}{5} < \frac{1}{4}

3 x^{2} - x - 7 = 0

x^{2} + 9 x + 8 = 0

x^{2} - 4 x = - 8

What are the solutions to the equation m^2+2m+6=0 ?
The solutions to the equation m^2+2m+6=0 are m=-1+sqrt(5)i,m=-1-sqrt(5)i
Find the zeros of m^2+2m+6=0
The zeros of m^2+2m+6=0 are m=-1+sqrt(5)i,m=-1-sqrt(5)i