What are the solutions to the equation 3y^2+5y-10=0 ?

The solutions to the equation 3y^2+5y-10=0 are y=(-5+sqrt(145))/6 ,y=(-5-sqrt(145))/6

Find the zeros of 3y^2+5y-10=0

The zeros of 3y^2+5y-10=0 are y=(-5+sqrt(145))/6 ,y=(-5-sqrt(145))/6

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3 y^{2} + 5 y - 10 = 0

y = \frac{- 5 + 145}{6}, y = \frac{- 5 - 145}{6}

Decimal Notation

y = 1.17359 \dots, y = - 2.84026 \dots

Solution steps

3 y^{2} + 5 y - 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 10) = 145

y_{1, 2} = \frac{- 5 \pm 145}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 5 + 145}{2 \cdot 3}, y_{2} = \frac{- 5 - 145}{2 \cdot 3}

y = \frac{- 5 + 145}{2 \cdot 3} : \frac{- 5 + 145}{6}

y = \frac{- 5 - 145}{2 \cdot 3} : \frac{- 5 - 145}{6}

The solutions to the quadratic equation are:

y = \frac{- 5 + 145}{6}, y = \frac{- 5 - 145}{6}

\frac{1 2 ^{2}}{4 ^{2}}

\frac{2}{7} x + \frac{2}{5} = \frac{19}{35}

\frac{5}{3} \cdot (- \frac{6}{7})

\frac{2 - 3 i}{1 - 2 i}

4 x^{2} + 9 x - 13 = 0

What are the solutions to the equation 3y^2+5y-10=0 ?
The solutions to the equation 3y^2+5y-10=0 are y=(-5+sqrt(145))/6 ,y=(-5-sqrt(145))/6
Find the zeros of 3y^2+5y-10=0
The zeros of 3y^2+5y-10=0 are y=(-5+sqrt(145))/6 ,y=(-5-sqrt(145))/6