What are the solutions to the equation 0=3t^2-36t+96 ?

The solutions to the equation 0=3t^2-36t+96 are t=8,t=4

Find the zeros of 0=3t^2-36t+96

The zeros of 0=3t^2-36t+96 are t=8,t=4

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0 = 3 t^{2} - 36 t + 96

t = 8, t = 4

Solution steps

0 = 3 t^{2} - 36 t + 96

Switch sides

3 t^{2} - 36 t + 96 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 3 \cdot 96}{2 \cdot 3}

(- 36)^{2} - 4 \cdot 3 \cdot 96 = 12

t_{1, 2} = \frac{- ( - 36 ) \pm 12}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 36 ) + 12}{2 \cdot 3}, t_{2} = \frac{- ( - 36 ) - 12}{2 \cdot 3}

t = \frac{- ( - 36 ) + 12}{2 \cdot 3} : 8

t = \frac{- ( - 36 ) - 12}{2 \cdot 3} : 4

The solutions to the quadratic equation are:

t = 8, t = 4

9 a^{5} b - 12 a^{2} b^{3} + 15 a b^{2} - 18 a^{3} b^{4}

(\frac{1}{27})^{2 x + 1} \leq (\frac{1}{243})^{3 x - 2}

i^{- 9}

- 2 m - 5 m - 8 = 3 + (- 7) + m

2 x^{2} + 5 x < - 3

What are the solutions to the equation 0=3t^2-36t+96 ?
The solutions to the equation 0=3t^2-36t+96 are t=8,t=4
Find the zeros of 0=3t^2-36t+96
The zeros of 0=3t^2-36t+96 are t=8,t=4