What is factor x^3-10x^2+28x-24 ?

The solution to factor x^3-10x^2+28x-24 is (x-2)^2(x-6)

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factor x^3-10x^2+28x-24

factor

x^{3} - 10 x^{2} + 28 x - 24

(x - 2)^{2} (x - 6)

Solution steps

x^{3} - 10 x^{2} + 28 x - 24

Use the rational root theorem

= (x - 2) \frac{x ^{3} - 10 x ^{2} + 28 x - 24}{x - 2}

\frac{x ^{3} - 10 x ^{2} + 28 x - 24}{x - 2} = x^{2} - 8 x + 12

= (x - 2) (x^{2} - 8 x + 12)

Factor

x^{2} - 8 x + 12 : (x - 2) (x - 6)

= (x - 2) (x - 2) (x - 6)

Apply exponent rule:

aa = a^{2}

(x - 2) (x - 2) = (x - 2)^{2}

= (x - 2)^{2} (x - 6)

x^{2} + 4 x - 12 \leq 0

\frac{5 ! 7 !}{3 ! 9 !}

- x^{2} + 4 x + 5

2 x^{2} + 15 x = 8 x - 5

\frac{8}{3} - 8

What is factor x^3-10x^2+28x-24 ?
The solution to factor x^3-10x^2+28x-24 is (x-2)^2(x-6)