What are the solutions to the equation x^2+9x=-26 ?

The solutions to the equation x^2+9x=-26 are x=-9/2+i(sqrt(23))/2 ,x=-9/2-i(sqrt(23))/2

Find the zeros of x^2+9x=-26

The zeros of x^2+9x=-26 are x=-9/2+i(sqrt(23))/2 ,x=-9/2-i(sqrt(23))/2

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x^{2} + 9 x = - 26

x = - \frac{9}{2} + i \frac{23}{2}, x = - \frac{9}{2} - i \frac{23}{2}

Solution steps

x^{2} + 9 x = - 26

Move

26

to the left side

x^{2} + 9 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

Simplify

9^{2} - 4 \cdot 1 \cdot 26 : 23 i

x_{1, 2} = \frac{- 9 \pm 23 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 23 i}{2 \cdot 1}, x_{2} = \frac{- 9 - 23 i}{2 \cdot 1}

x = \frac{- 9 + 23 i}{2 \cdot 1} : - \frac{9}{2} + i \frac{23}{2}

x = \frac{- 9 - 23 i}{2 \cdot 1} : - \frac{9}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

x = - \frac{9}{2} + i \frac{23}{2}, x = - \frac{9}{2} - i \frac{23}{2}

3 x - 5 \geq - 11

7 + 5 b - 3 b^{2} = 8

\frac{50 + 8}{20 - 7}

2 w^{2} - 4 w + 5 = 0

- 2 = - 2 x + 4

What are the solutions to the equation x^2+9x=-26 ?
The solutions to the equation x^2+9x=-26 are x=-9/2+i(sqrt(23))/2 ,x=-9/2-i(sqrt(23))/2
Find the zeros of x^2+9x=-26
The zeros of x^2+9x=-26 are x=-9/2+i(sqrt(23))/2 ,x=-9/2-i(sqrt(23))/2