What are the solutions to the equation (5k-4)^2=36 ?

The solutions to the equation (5k-4)^2=36 are k=2,k=-2/5

Find the zeros of (5k-4)^2=36

The zeros of (5k-4)^2=36 are k=2,k=-2/5

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(5 k - 4)^{2} = 36

k = 2, k = - \frac{2}{5}

Decimal Notation

k = 2, k = - 0.4

Solution steps

(5 k - 4)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 k - 4 = 36 : k = 2

Solve

5 k - 4 = - 36 : k = - \frac{2}{5}

The solutions to the quadratic equation are:

k = 2, k = - \frac{2}{5}

9 x^{2} - 7 x - 5 = 0

\frac{( 300 P + 6000 )}{300 P} = 35%

\frac{- 6 x ^{2} - 2 e ^{y}}{3 x ^{2} y + e ^{y}}

3 x^{2} + 17 x - 28

- {4 (d + 3) - 5 [3 d - 2 (2 d + 7)] - 8} = - 10 d - 6

What are the solutions to the equation (5k-4)^2=36 ?
The solutions to the equation (5k-4)^2=36 are k=2,k=-2/5
Find the zeros of (5k-4)^2=36
The zeros of (5k-4)^2=36 are k=2,k=-2/5