What are the solutions to the equation 0=3x^2+5x+4 ?

The solutions to the equation 0=3x^2+5x+4 are x=-5/6+i(sqrt(23))/6 ,x=-5/6-i(sqrt(23))/6

Find the zeros of 0=3x^2+5x+4

The zeros of 0=3x^2+5x+4 are x=-5/6+i(sqrt(23))/6 ,x=-5/6-i(sqrt(23))/6

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0 = 3 x^{2} + 5 x + 4

x = - \frac{5}{6} + i \frac{23}{6}, x = - \frac{5}{6} - i \frac{23}{6}

Solution steps

0 = 3 x^{2} + 5 x + 4

Switch sides

3 x^{2} + 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

Simplify

5^{2} - 4 \cdot 3 \cdot 4 : 23 i

x_{1, 2} = \frac{- 5 \pm 23 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 23 i}{2 \cdot 3}, x_{2} = \frac{- 5 - 23 i}{2 \cdot 3}

x = \frac{- 5 + 23 i}{2 \cdot 3} : - \frac{5}{6} + i \frac{23}{6}

x = \frac{- 5 - 23 i}{2 \cdot 3} : - \frac{5}{6} - i \frac{23}{6}

The solutions to the quadratic equation are:

x = - \frac{5}{6} + i \frac{23}{6}, x = - \frac{5}{6} - i \frac{23}{6}

\frac{( 3 m ^{- 2} n ) ^{- 3}}{6 m n ^{- 2}}

(\frac{1}{5})^{7}

x - 2 = 1

x^{2} - x - 16 = 0

\frac{4}{9} + \frac{1}{6}

What are the solutions to the equation 0=3x^2+5x+4 ?
The solutions to the equation 0=3x^2+5x+4 are x=-5/6+i(sqrt(23))/6 ,x=-5/6-i(sqrt(23))/6
Find the zeros of 0=3x^2+5x+4
The zeros of 0=3x^2+5x+4 are x=-5/6+i(sqrt(23))/6 ,x=-5/6-i(sqrt(23))/6