What are the solutions to the equation -x^2+81=0 ?

The solutions to the equation -x^2+81=0 are x=9,x=-9

Find the zeros of -x^2+81=0

The zeros of -x^2+81=0 are x=9,x=-9

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- x^{2} + 81 = 0

x = 9, x = - 9

Solution steps

- x^{2} + 81 = 0

Move

81

to the right side

- x^{2} = - 81

Divide both sides by

- 1

x^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 81, x = - 81

81 = 9

- 81 = - 9

x = 9, x = - 9

15 x \leq x^{2} + 56

- 3 x - 10 < 21 + 8 x

\frac{y ^{\frac{3}{2}}}{y ^{\frac{1}{2}} + 2}

x (x - 2) (x + 4) \leq 0

6 x^{2} + 18 x + 12

What are the solutions to the equation -x^2+81=0 ?
The solutions to the equation -x^2+81=0 are x=9,x=-9
Find the zeros of -x^2+81=0
The zeros of -x^2+81=0 are x=9,x=-9