What is the answer to |x+1|+|x-1|=2 ?

The answer to |x+1|+|x-1|=2 is -1<= x<= 1

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|x+1|+|x-1|=2

∣ x + 1 ∣ + ∣ x - 1 ∣ = 2

- 1 \leq x \leq 1

Solution steps

∣ x + 1 ∣ + ∣ x - 1 ∣ = 2

Find positive and negative intervals

x < - 1, - 1 \leq x < 1, x \geq 1

Solve the inequality for each interval

No Solution or - 1 \leq x < 1 or x = 1

Merge Overlapping Intervals

- 1 \leq x \leq 1

(2 x + 7) (2 x - 7) = 0

\frac{( 1 + i ) ( 1 - i ) ^{4}}{( 1 + 2 i ) ^{3}}

∣ x ∣ \geq 9

1 < 3 x - 2 < 4

2 + 2 p \leq 10