What are the solutions to the equation 28-7x^2=0 ?

The solutions to the equation 28-7x^2=0 are x=2,x=-2

Find the zeros of 28-7x^2=0

The zeros of 28-7x^2=0 are x=2,x=-2

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28 - 7 x^{2} = 0

x = 2, x = - 2

Solution steps

28 - 7 x^{2} = 0

Move

28

to the right side

- 7 x^{2} = - 28

Divide both sides by

- 7

x^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4, x = - 4

4 = 2

- 4 = - 2

x = 2, x = - 2

3 p^{2} + 14 p - 24

1 x^{2} + 2 x + 3 = 0

2 x - \frac{1}{2} \geq 7 x + \frac{7}{6}

\frac{4}{9} - \frac{5}{8} (\frac{1}{3})^{2}

∣ x - 3 ∣ = - 2

What are the solutions to the equation 28-7x^2=0 ?
The solutions to the equation 28-7x^2=0 are x=2,x=-2
Find the zeros of 28-7x^2=0
The zeros of 28-7x^2=0 are x=2,x=-2