What is -4k^2+16k>0 ?

The solution to -4k^2+16k>0 is 0<k<4

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-4k^2+16k>0

- 4 k^{2} + 16 k > 0

0 < k < 4

Interval Notation

(0, 4)

Solution steps

- 4 k^{2} + 16 k > 0

Rewrite in standard form

- k^{2} + 4 k > 0

Factor

- k^{2} + 4 k : - k (k - 4)

- k (k - 4) > 0

Multiply both sides by

- 1

(reverse the inequality)

(- k (k - 4)) (- 1) < 0 \cdot (- 1)

Simplify

k (k - 4) < 0

Identify the intervals

0 < k < 4

64 n^{4} - 192 n^{3} + 27 n - 81

- \frac{1}{4} x + \frac{3}{8} \leq 1

2 x^{4} r - 72 y^{4} r

18 x^{3} y^{4} - 39 x^{4} y^{3}

- 5 x + 1 - 2 (x + 1) = 4 x + 6