What are the solutions to the equation x^2-14x-95=0 ?

The solutions to the equation x^2-14x-95=0 are x=19,x=-5

Find the zeros of x^2-14x-95=0

The zeros of x^2-14x-95=0 are x=19,x=-5

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x^{2} - 14 x - 95 = 0

x = 19, x = - 5

Solution steps

x^{2} - 14 x - 95 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 95 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 95) = 24

x_{1, 2} = \frac{- ( - 14 ) \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 24}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 24}{2 \cdot 1}

x = \frac{- ( - 14 ) + 24}{2 \cdot 1} : 19

x = \frac{- ( - 14 ) - 24}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 19, x = - 5

12 x^{2} + 11 x + 2 = 0

m + 4 < 0

k^{2} = 14

\frac{1}{P ( M - P )} d P

25 x^{2} - 15 = 0

What are the solutions to the equation x^2-14x-95=0 ?
The solutions to the equation x^2-14x-95=0 are x=19,x=-5
Find the zeros of x^2-14x-95=0
The zeros of x^2-14x-95=0 are x=19,x=-5