What are the solutions to the equation 8x^2+1=17 ?

The solutions to the equation 8x^2+1=17 are x=sqrt(2),x=-sqrt(2)

Find the zeros of 8x^2+1=17

The zeros of 8x^2+1=17 are x=sqrt(2),x=-sqrt(2)

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8 x^{2} + 1 = 17

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

8 x^{2} + 1 = 17

Move

1

to the right side

8 x^{2} = 16

Divide both sides by

8

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

1 5^{2} = x^{2} + (x + 3)^{2}

\frac{a ^{4} b ^{6}}{a b ^{3}}

75 x + 57 = - 75 x + 57

\frac{5}{2 - 4 i}

9 \geq 5 x + 4 \geq 2

What are the solutions to the equation 8x^2+1=17 ?
The solutions to the equation 8x^2+1=17 are x=sqrt(2),x=-sqrt(2)
Find the zeros of 8x^2+1=17
The zeros of 8x^2+1=17 are x=sqrt(2),x=-sqrt(2)