What are the solutions to the equation 4x^2-6x+9=0 ?

The solutions to the equation 4x^2-6x+9=0 are x= 3/4+i(3sqrt(3))/4 ,x= 3/4-i(3sqrt(3))/4

Find the zeros of 4x^2-6x+9=0

The zeros of 4x^2-6x+9=0 are x= 3/4+i(3sqrt(3))/4 ,x= 3/4-i(3sqrt(3))/4

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4 x^{2} - 6 x + 9 = 0

x = \frac{3}{4} + i \frac{3 3}{4}, x = \frac{3}{4} - i \frac{3 3}{4}

Solution steps

4 x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

Simplify

(- 6)^{2} - 4 \cdot 4 \cdot 9 : 63 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 3 i}{2 \cdot 4}, x_{2} = \frac{- ( - 6 ) - 6 3 i}{2 \cdot 4}

x = \frac{- ( - 6 ) + 6 3 i}{2 \cdot 4} : \frac{3}{4} + i \frac{3 3}{4}

x = \frac{- ( - 6 ) - 6 3 i}{2 \cdot 4} : \frac{3}{4} - i \frac{3 3}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} + i \frac{3 3}{4}, x = \frac{3}{4} - i \frac{3 3}{4}

5 (x - 4)^{2} = 5

\frac{x ^{2} - 1}{5} = 7

- \frac{3}{5} - 1

(\frac{1}{3})^{7}

x^{2} + x + 1 > 0

What are the solutions to the equation 4x^2-6x+9=0 ?
The solutions to the equation 4x^2-6x+9=0 are x= 3/4+i(3sqrt(3))/4 ,x= 3/4-i(3sqrt(3))/4
Find the zeros of 4x^2-6x+9=0
The zeros of 4x^2-6x+9=0 are x= 3/4+i(3sqrt(3))/4 ,x= 3/4-i(3sqrt(3))/4