What are the solutions to the equation y^2-90=13y ?

The solutions to the equation y^2-90=13y are y=18,y=-5

Find the zeros of y^2-90=13y

The zeros of y^2-90=13y are y=18,y=-5

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y^{2} - 90 = 13 y

y = 18, y = - 5

Solution steps

y^{2} - 90 = 13 y

Move

13 y

to the left side

y^{2} - 90 - 13 y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - 13 y - 90 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot ( - 90 )}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot (- 90) = 23

y_{1, 2} = \frac{- ( - 13 ) \pm 23}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 13 ) + 23}{2 \cdot 1}, y_{2} = \frac{- ( - 13 ) - 23}{2 \cdot 1}

y = \frac{- ( - 13 ) + 23}{2 \cdot 1} : 18

y = \frac{- ( - 13 ) - 23}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

y = 18, y = - 5

∣ x - 2 ∣ < 9

3 x^{2} + 17 x - 6 = 0

\frac{80 \cdot 20}{100}

i + 6 i

8 m^{3} n - 32 m^{2} n^{2} + 24 mn

What are the solutions to the equation y^2-90=13y ?
The solutions to the equation y^2-90=13y are y=18,y=-5
Find the zeros of y^2-90=13y
The zeros of y^2-90=13y are y=18,y=-5