What is 1/x+1/(x+1)< 2/(x+9) ?

The solution to 1/x+1/(x+1)< 2/(x+9) is -9<x<-1\lor-9/17 <x<0

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1/x+1/(x+1)< 2/(x+9)

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 9}

- 9 < x < - 1 or - \frac{9}{17} < x < 0

Interval Notation

(- 9, - 1) \cup (- \frac{9}{17}, 0)

Decimal Notation

- 9 < x < - 1 or - 0.52941 \dots < x < 0

Solution steps

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 9}

Rewrite in standard form

\frac{17 x + 9}{x ( x + 1 ) ( x + 9 )} < 0

Identify the intervals

- 9 < x < - 1 or - \frac{9}{17} < x < 0

11 \geq 3 x + 2 and 20 - 3 (x + 2) \leq 5

v^{2} + 21 = - 8 v + 6

8 x^{2} - 65 x + 35 = 0

ln (\frac{1}{e ^{3}})

p + \frac{1}{3} (p + 1) + \frac{1}{4} (p + 2) = \frac{5}{6}

What is 1/x+1/(x+1)< 2/(x+9) ?
The solution to 1/x+1/(x+1)< 2/(x+9) is -9<x<-1\lor-9/17 <x<0